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12V, 125mA Isolated Step-Up Voltage Regulator U5Z9F12 |
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QTRXL-MD-01A-S Reflectance Sensor: 1-Channel, 8mm Wide, Analog Output, Long Range, Side-Entry Connector |
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Glideforce GF01-121005-1-66 Micro Linear Actuator with Limit Switches: 12V, 4.3kgf, 17.6mm/s, 50mm Stroke |
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4.4:1 Metal Gearmotor 25Dx48L mm HP 24V |
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HP 24V Motor with 48 CPR Encoder for 25D mm Metal Gearmotors (No Gearbox) |
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ISO6540F 4-Channel Digital Isolator Carrier, 4/0, Default Low, Functional Isolation |
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TPS2116 Power Multiplexer Carrier with USB Type-C Connector (non-USB priority) |
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5V, 300mA Isolated Step-Down Voltage Regulator D24Z3F5 |
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QTR-MD-01A-S Reflectance Sensor: 1-Channel, 8mm Wide, Analog Output, Side-Entry Connector |
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ACS37100LMATR-050B3 TMR Current Sensor Large Carrier -50A to +50A, 3.3V |
Understanding battery capacity: Ah is not A
- 18 January 2016Thank you for the quick and thoughtful response! I am also unsure as to how finicky these fans are; supposedly they are standard 5V small computer fans but probably super cheaply made and I don't want to risk overheating or ruining the batteries.
I hadn't thought of having two parallel systems... It sounds like a good idea if parallel batteries is a bad idea. I think I will go with that plan instead. Thanks again!
Understanding battery capacity: Ah is not A
- 16 January 2016Hello Jan, thank you for the informative article.
I thought initially that I knew what I was doing, but your comment about "not using parallel unless you know what you're doing" threw me off a bit.
What I want to do is run a group of six 5v fans, each drawing 120mA, from a battery pack (so the total draw should be 120x6=720mA). The run time needs to be 3-5 hours.
My original plan was to use two packs of 4 NiMH AA batteries (2500mAh each), in parallel. 8 batteries total.
By my calculations, that would provide a total of 4.8v and 5000mAh to the fans. So the run time would be 5000/720 = 6.9 hours at absolute maximum.
Do I have it correct? Many thanks!