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CT432-HSWF30DR TMR Current Sensor Compact Carrier 0A to 30A, 5V |
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0.100″ (2.54 mm) Breakaway Male Header: 1×10-Pin, Straight, Black, 25-Pack |
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JST SH-Style Cable, 4-Pin, Female-Female, 63cm |
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JST PH-Style Cable with Female Pins for 0.1" Housings, 3-Pin, 75cm |
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Pololu Reverse Voltage Protector, 4-60V, 25A |
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ACS72981ELRATR-200B3 Current Sensor Compact Carrier -200A to +200A, 3.3V |
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Pololu Digital Distance Sensor v2 with Pulse Width Output, 50cm Max, Side-Entry Connector |
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Isolated DC-DC Power Module, MIE1W0505BGLVH, 5V/3.3V, 200mA |
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ACS37800KMACTR-030B3-I2C Power Monitor Carrier with Secondary I²C Isolation (Soldered Terminal Block, 240VRMS Jumper) |
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Pololu I²C Isolator, ISO1640 |
Understanding battery capacity: Ah is not A
- 18 January 2016Thank you for the quick and thoughtful response! I am also unsure as to how finicky these fans are; supposedly they are standard 5V small computer fans but probably super cheaply made and I don't want to risk overheating or ruining the batteries.
I hadn't thought of having two parallel systems... It sounds like a good idea if parallel batteries is a bad idea. I think I will go with that plan instead. Thanks again!
Understanding battery capacity: Ah is not A
- 16 January 2016Hello Jan, thank you for the informative article.
I thought initially that I knew what I was doing, but your comment about "not using parallel unless you know what you're doing" threw me off a bit.
What I want to do is run a group of six 5v fans, each drawing 120mA, from a battery pack (so the total draw should be 120x6=720mA). The run time needs to be 3-5 hours.
My original plan was to use two packs of 4 NiMH AA batteries (2500mAh each), in parallel. 8 batteries total.
By my calculations, that would provide a total of 4.8v and 5000mAh to the fans. So the run time would be 5000/720 = 6.9 hours at absolute maximum.
Do I have it correct? Many thanks!